169x^2-104x+16=0

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Solution for 169x^2-104x+16=0 equation: 



169x^2-104x+16=0

a = 169; b = -104; c = +16;
Δ = b2-4ac
Δ = -1042-4·169·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{104}{338}=4/13$

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